Write a file named `quadratic.py`

with a function named `big_root`

which, if given (a, b, c), returns the more positive root of the quadratic equation

a

x^{2}+ bx+ c = 0

Use the quadratic formula to solve this problem.

Also write a second function, `small_root`

, which gives the other root of the equation.

You may assume we only give coefficients for which the answer is a real number.

Neither function should `print`

anything nor ask for any `input`

. You should not have any code outside of these two functions.

When you run `quadratic.py`

, nothing should happen. It defines a function, it does not run it.

If in another file (which you do not submit) you write the following:

```
import quadratic
print(quadratic.big_root(1, -1, -1))
print(quadratic.small_root(1, -1, -1))
```

you should get the following output:

```
1.618033988749895
-0.6180339887498949
```

(don’t worry if your answer differs in the last few digits)

We won’t grade this, but what does your code do when you try to solve an equation with no real solutions?

`print(quadratic.big_root(1, 1, 1))`

If you want, feel free to also add the cubic formula or even (if you feel really ambitious) the quartic formula, but there isn’t a quintic formula.

Recall that .

Don’t remember the operators you need? See §3.3.1. Also, remember that in Python `^`

is *not* the exponentiation operator (we won’t cover what `^`

is; if you are curious, see §19.2.5).

Did you get the order of operations right? You could look them up, but adding parentheses never hurts.

There are two roots (because of the ± in the quadratic formula), but one of them is always the biggest… no need for an `if`

Have you tried other coefficients besides `(1, -1, -1)`

?